crzymdups wrote:BigSm00th wrote:martin wrote:BigSm00th wrote:2012 lakers:(assuming a 57 million cap)
they have a player option on bynum and paul will be a FA. i believe they can let both of them "wink wink" become free agents.
they have blake and fisher making a combined $7.4 million. kobe at 27 million. that puts total team around $34 million. they amnetsy either luke walton ($6 million) or artest ($7 million). assuming they do luke, they'd still have around 17 mil to offer a max deal to dwight.
so they offer a max to dwight, and then they can go over the cap to re-sign their own free agents. i think that's how it works. so you assume they go over the cap to sign CP3 and bynum, and, while they will be paying an absolutley ungodly amount in luxury tax (they'll be like 25 million over the cap; prob will pay like 50 mil a year in tax at least), they will field:
PG - CP3
SG- Kobe
SF - "metta world peace"
PF - bynum
C - howard
with blake and fisher off the bench. and then probably a bunch of guys playing for the veteran minimum chasing rings.
i can't remember a day this insane
cap holds for cp3/bynum? not sure your scenario works out. you can only sign your own free agents OVER the cap if they are still yours... meaning they have cap holds, right?
not sure; you may be right. i think CP3 can become a free agent, IE his contract just ends and he will be off the books. and bynum has a player opt out, so i'm assuming both will be on the market, and lakers can sign howard first, and then the other 2. but i could be wrong.
i think if the Lakers get Dwight, it'll definitely be a sign and trade involving Bynum.
you can't have Bynum and Dwight on the same team. makes no sense.
the money'll work... i think. but who knows?
They can certainly do a sign and trade for Dwight and Bynum, but they would have to renounce CP3. Howard = ~$20M, Kobe = $25M, that's $45M total, plus cap holds, etc. Luke Walton and Steve Blake take another $10M, that's $57M. No way can they fit CP3, Kobe, Howard on same team.