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Jalen Brunson named the Eastern Conference Player of the Week

For the fourth time this season

Chicago Bulls v New York Knicks Photo by Elsa/Getty Images

In a crucial last week of the regular season that started with the Knicks not knowing what seed they’d go into the playoffs as, Jalen Brunson, as he has all season long, came up big and has been named as the Eastern Conference Player of the Week. The All-Star point guard averaged 38.5PPG, 7.5APG, and 3.5RPG while leading New York to a perfect 4-0 record en route to securing the franchise’s first 50-win season since 2013. Brunson, who last received the award on March 18th, has now won four Player of the Week awards this season and has won five since coming over to New York last season. To put that into perspective, that’s tied for the most in the league this season with Luka Doncic and is more than Steph Curry, Kyrie Irving, and Donovan Mitchell have combined.

Winning the award in the Western Conference is Nikola Jokic, who averaged 26.5 PPG, 11.5 RPG, and 7.8 APG to lead the Nuggets to a 3-1 record. Jokic, like Brunson, leads his team to the number two seed and finds himself right in the thick of the MVP conversations once again.